I graphed a line in the x y plane that begins at (-9,6) and stops at (2,4). This is because a college algebra book asked to consider the distance FROM P1 (-9,6) TO P2 (2,4). The authors then mention that the "midpoint formula is a bit more complex that i

I graphed a line in the x y plane that begins at  (-9,6) and stops at (2,4). This is because a college algebra book asked to consider the distance FROM P1 (-9,6) TO P2 (2,4). The authors then mention that the "midpoint formula is a bit more complex that it looks and is actualy a special case of a geometric theorem. Something about the ratios of the distances. Exploring this I then decided to use the mathcad software to create the two right triangles that would be associated with these three points. The point (answer) is P3 (-23/5,26/5). The reason I wanted to create these two right triangles is just to explore my ability to integrate the areas and compare the ratios. And I did it!  My graph of the line that starts and stops at P1 and P2 is defined as f(x). To make the two triangles I wrote a program g(x) that uses inequalities and operators. In the placeholder for x and y however the g(x) is stated as g(a) and the x placeholder is x,a. I am not able to post a worksheet. But if anyone can visualize this Algebra problem and plot this scenario I would much appreciate it.